How To Make Login Form With JQuery In PHP

Submitted by alpha_luna on Tuesday, August 4, 2015 - 14:44.

Language

Good Day!!!

Related Code: How To Make Register Form with JQuery Validation In this tutorial, we are going to learn How To Make Login Form With JQuery In PHP. This is simple project and it consists username and password.

Username

tutorial

Password

admin

Database Name

login_jquery

You can use it to your Website or System. Download the source code and try it. Enjoy Coding...

Directions:

For JQuery Code

<script type="text/javascript">
$(document).ready(function() {
$("#submit").click(function() {
    var username = $("#username").val();        
        var password = $("#password").val();
        if(username=='' || password=='' ){ 
        alert("Please enter the username and password");
        }
        else {          
    $.ajax({
    type: "POST",
    url: "login_function.php",
    data:  "username="+ username + "&password=" + password ,
        
        beforeSend: function() 
                {
                        $('#display_query').html('Loading....');
                },  
                success: function(response)
                {
                        $("#display_query").fadeIn(2000).html(response);
                        
                        document.getElementById('username').value='';
                document.getElementById('password').value='';
                        
                } 
});
}               
    return false;
        });
        
});
</script>

For PHP Code

<!---
Welcome to the Sourcecodester.com
For more tutorials, kindly visit our website:
 
http://www.sourcecodester.com/
-->
<?php
$db = mysql_connect('localhost','root','') or die ("Unable to connect to Database Server.");
mysql_select_db ('login_jquery', $db) or die ("Could not select database.");
 
if(isset($_POST['username']))
{
 $username=$_POST['username'];
 $password=$_POST['password'];
 $query = mysql_query("select * from user  where username='$username' and password='$password' ")or die(mysql_error());                 
                $data = mysql_fetch_row($query);
                if($data){      
                echo '<div id="sucess"><img src="image/success.png"></div>';}
                else {
                echo '<div id="error"><img src="image/invalid.png"></div>';}
 
}?>

For CSS Code

<style type="text/css">
#display_query {
        display:none;
        border-radius:3px;
        margin-bottom:4px;
}
 
table {
        width:300px;
        float:left;
}
 
label {
        color:blue;
        font-size:20px;
        font-weight:bold;
}
 
.text_style {
        font-size:18px;
        text-indent:5px;
}
 
.btn_style {
        font-size:18px;
        border:3px groove #CCC;
        border-radius:7px;
        width:100px;
        font-weight:bold;
}
</style>

For HTML Code

<form method="post" name="form" action="">
<table cellspacing="4" cellpadding="4">
        <tr style="background-color:#000000;">
                <td colspan="2" align="center">
                        <h2 style="color:#FFFFFF;">Enter the details below...</h2>
                </td>
        </tr>
        <tr>
                <td>
                        <label>Username</label>
                </td>
                <td>
                        <input name="username" class="text_style" placeholder="Username..." type="text" id="username" />
                </td>
        </tr>
        <tr>
                <td>
                        <label>Password</label>
                </td>
                <td>
                        <input name="password" class="text_style" placeholder="Password..." type="password" id="password" />
                </td>
        </tr>
        <tr>
                <td colspan="2" align="center">
                        <input type="submit" class="btn_style" name="submit" value="Submit" id="submit" />
                </td>
        </tr>
        <tr>
                <td colspan="2">
                        <div align="center" id="display_query"></div>
                </td>
        </tr>
</table>
</form>
 
<table style="margin-left:100px;">
        <tr>
                <td>
                        <label>Database Name</label>
                </td>
                <td>
                        <span style="color:red;">login_jquery</span>
                </td>
        </tr>
        <tr>
                <td>
                        <label>Username</label>
                </td>
                <td>
                        <span style="color:red;">tutorial</span>
                </td>
        </tr>
        <tr>
                <td>
                        <label>Password</label>
                </td>
                <td>
                        <span style="color:red;">admin</span>
                </td>
        </tr>
</table>
 
<a href="http://www.sourcecodester.com" style="float:right;">
        <h3>
                Sourcecodester
        </h3>
</a>

Related Code: How To Make Register Form with JQuery Validation So what can you say about this work? Share your thoughts in the comment section below or email me at [email protected]. Practice Coding. Thank you.

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