Classify Numbers in Java

Submitted by GeePee on Saturday, May 23, 2015 - 22:32.
The following Java program application counts the number of odd and even numbers. The program also counts the number of zeros. I will be using the JCreator IDE in developing the program. To start in this tutorial, first open the JCreator IDE, click new and paste the following code. 
  1. import java.util.*;
  2. public class ClassifyNumbers
  3. {
  4. 	static Scanner console = new Scanner (System.in);
  5.  
  6. 	static final int N = 20;
  7.  
  8. 	public static void main (String[] args)
  9. 	{
  10. 		//declare variables
  11.  
  12. 		int counter;  //loop control variable
  13. 		int number; //variable to store the new number
  14.  
  15. 		int zeros = 0;
  16. 		int odds = 0;
  17. 		int evens = 0;
  18.  
  19. 		System.out.println("Please enter " + N
  20. 			+ " integers, positive, negative, or zeros: ");
  21.  
  22. 			for (counter = 1; counter <= N; counter++)
  23. 			{
  24. 				number  = console.nextInt();
  25. 				System.out.print(number + " ");
  26.  
  27. 				switch (number % 2)
  28. 				{
  29. 					case 0: evens++;
  30. 						if (number == 0)
  31. 							zeros++;
  32. 					break;
  33. 					case 1:
  34. 						case -1: odds++;
  35. 				}
  36. 			}
  37. 			System.out.println();
  38. 			System.out.println("There are " + evens + "evens "
  39. 				+ "which also includes " 
  40. 					+ zeros + " zeros");
  41. 			System.out.println("Total number of odds is: " + odds);
  42. 	}
  43. }
Sample run: 
  1. Please enter 20 integers, positive, negative, or zeros: 
  2. 1 2 3 4 5 6 7 8 9 0 -1 -2 -3 -4 -5 -6 -7 -8 -9 0
  3. 1 2 3 4 5 6 7 8 9 0 -1 -2 -3 -4 -5 -6 -7 -8 -9 0 
  4. There are 10evens which also includes 2 zeros
  5. Total number of odds is: 10
The program work as follows: The statement 
  1.  System.out.println("Please enter " + N
  2. 			+ " integers, positive, negative, or zeros: "); prompts the user to enter integers, positive, negative or zero numbers.
  3.  
  4. The statement <java number  = console.nextInt();
  5. 				System.out.print(number + " ");
gets the next number and outputs the number. The statement  for (counter = 1; counter <= N; counter++) process and analyze the 20 numbers. The statement 
  1.  System.out.println("There are " + evens + "evens "
  2. 				+ "which also includes " 
  3. 					+ zeros + " zeros");
  4. 			System.out.println("Total number of odds is: " + odds);
print the result and output the values of the variables zeros, evens and odds.

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